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Physics · 2021

JEE Main · 27 July 2021, Shift 2 · Q23

In the given figure the magnetic flux through the loop increases according to the relation φ_β(t)=10 t^2+20 t, where φ_β is in milliwebers and t is…

In the given figure the magnetic flux through the loop increases according to the relation $\displaystyle \phi_\beta(t)=10 t^2+20 t$, where $\displaystyle \phi_\beta$ is in milliwebers and $\displaystyle t$ is in seconds. The magnitude of current through $\displaystyle \mathrm{R}=2 \Omega$ resistor at $\displaystyle t=5 \mathrm{~s}$ is \_\_\_\_ mA. Figure: JEE Main Physics 2021, Electromagnetic Induction
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.