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Physics · 2019

JEE Main · 12 January 2019, Shift 2 · Q27

In the figure, given that V_BB supply can vary from 0 to 5.0 V, V_CC =5 V, β_dc =200, R_B =100 k Ω, R_C =1 k Ω and V_BE =1.0 V, The minimum base…

Figure: JEE Main Physics 2019, Semiconductor Electronics In the figure, given that $\displaystyle \mathrm{V}_{\mathrm{BB}}$ supply can vary from $\displaystyle 0$ to $\displaystyle 5.0 \mathrm{~V}, \mathrm{~V}_{\mathrm{CC}}=5 \mathrm{~V}, \beta_{\mathrm{dc}}=200$, $\displaystyle \mathrm{R}_{\mathrm{B}}=100 \quad \mathrm{k} \Omega, \quad \mathrm{R}_{\mathrm{C}}=1 \quad \mathrm{k} \Omega$ and $\displaystyle \mathrm{V}_{\mathrm{BE}}=1.0 \mathrm{~V}$, The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively :
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.