Physics · 2014
JEE Main · 11 April 2014, Shift 1 · Q1
In terms of resistance R and time T, the dimensions of ratio (μ)/(ε) of the permeability μ and permittivity ε is:
In terms of resistance R and time T, the dimensions of ratio $\displaystyle \frac{\mu}{\epsilon}$ of the permeability $\displaystyle \mu$ and permittivity $\displaystyle \epsilon$ is :
Official answer
(3)
$\displaystyle \left[\mathrm{R}^2\right]$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.