Physics · 2019
JEE Main · 10 April 2019, Shift 2 · Q15
In free space, a particle A of charge 1 μ C is held fixed at a point P. Another particle B of the same charge and mass 4 μ g is kept at a distance of…
In free space, a particle A of charge $\displaystyle 1 \mu \mathrm{C}$ is held fixed at a point P. Another particle B of the same charge and mass $\displaystyle 4 \mu \mathrm{~g}$ is kept at a distance of $\displaystyle 1$ mm from P . If B is released, then its velocity at a distance of $\displaystyle 9$ mm from P is :
$$\left[\text { Take } \frac{1}{4 \pi \epsilon_{\mathrm{o}}}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right]
$$
Official answer
(2)
$\displaystyle 2.0 \times 10^3 \mathrm{~m} / \mathrm{s}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.