Physics · 2024
JEE Main · 6 April 2024, Shift 2 · Q50
In finding out refractive index of glass slab the following observations were made through travelling microscope 50 vernier scale division =49 MSD;…
In finding out refractive index of glass slab the following observations were made through travelling microscope $\displaystyle 50$ vernier scale division $\displaystyle =49 \mathrm{MSD}$; $\displaystyle 20$ divisions on main scale in each cm
For mark on paper
$$\text { MSR }=8.45 \mathrm{~cm}, \mathrm{VC}=26
$$
For mark on paper seen through slab
$$\mathrm{MSR}=7.12 \mathrm{~cm}, \mathrm{VC}=41
$$
For powder particle on the top surface of the glass slab
$$\mathrm{MSR}=4.05 \mathrm{~cm}, \mathrm{VC}=1
$$
(MSR = Main Scale Reading, VC = Vernier Coincidence)
Refractive index of the glass slab is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 1.42$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.