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Physics · 2023

JEE Main · 1 February 2023, Shift 1 · Q22

In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.5 V is found to be 60 cm. If this cell is…

In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf $\displaystyle 1.5$ V is found to be $\displaystyle 60$ cm . If this cell is replaced by another cell of emf E, the length-of null point increases by $\displaystyle 40$ cm . The value of $\displaystyle E$ is $\displaystyle \frac{x}{10} V$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.