Physics · 2021
JEE Main · 25 July 2021, Shift 1 · Q4
In Amplitude Modulation, the message signal V_m (t)=10 sin (2 π × 10^5 t) volts and Carrier signal V_c(t)=20 sin (2 π × 10^7 t) volts The modulated…
In Amplitude Modulation, the message signal
$$\mathrm{V}_{\mathrm{m}}(t)=10 \sin \left(2 \pi \times 10^5 t\right) \text { volts and }
$$
Carrier signal
$$V_c(t)=20 \sin \left(2 \pi \times 10^7 t\right) \text { volts }
$$
The modulated signal now contains the message signal with lower side band and upper side band frequency, therefore the bandwidth of modulated signal is $\displaystyle \alpha \mathrm{kHz}$.
The value of $\displaystyle \alpha$ is :
Official answer
(1)
$\displaystyle 200$ kHz
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.