SolveIt is under development
SolveItJEE Main
Question 138 / 140 · latest first
Physics · 2020

JEE Main · 7 January 2020, Shift 2 · Q17

In a Young's double slit experiment, the separation between the slits is 0.15 mm. In the experiment, a source of light of wavelength 589 nm is used…

In a Young's double slit experiment, the separation between the slits is $\displaystyle 0.15$ mm. In the experiment, a source of light of wavelength $\displaystyle 589$ nm is used and the interference pattern is observed on a screen kept $\displaystyle 1.5$ m away. The separation between the successive bright fringes on the screen is :
ShareWhatsAppTelegram

More from Wave Optics

JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.