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Physics · 2024

JEE Main · 9 April 2024, Shift 1 · Q59

In a Young's double slit experiment, the intensity at a point is (1/4)^th of the maximum intensity, the minimum distance of the point from the…

In a Young's double slit experiment, the intensity at a point is $\displaystyle \left(\frac{1}{4}\right)^{\text {th }}$ of the maximum intensity, the minimum distance of the point from the central maximum is $\displaystyle \_\_\_\_$ $\displaystyle \mu \mathrm{m}$. (Given : $\displaystyle \lambda=600 \mathrm{~nm}, \mathrm{~d}=1.0 \mathrm{~mm}, \mathrm{D}=1.0 \mathrm{~m}$ )
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.