Physics · 2021
JEE Main · 26 February 2021, Shift 1 · Q1
In a typical combustion engine the workdone by a gas molecule is given by W =α^2 β e^((-β x^2)/(k T)), where x is the displacement, k is the…
In a typical combustion engine the workdone by a gas molecule is given by $\displaystyle \mathrm{W}=\alpha^2 \beta \mathrm{e}^{\frac{-\beta x^2}{k \mathrm{~T}}}$, where $\displaystyle x$ is the displacement, $\displaystyle k$ is the Boltzmann constant and T is the temperature. If $\displaystyle \alpha$ and $\displaystyle \beta$ are constants, dimensions of $\displaystyle \alpha$ will be :
Official answer
(2)
$\displaystyle \left[\mathrm{M}^0 \mathrm{~L} \mathrm{~T}^0\right]$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.