Physics · 2018
JEE Main · 15 April 2018, Shift 1 · Q30
In a screw gauge, 5 complete rotations of the screw cause it to move a linear distance of 0.25 cm. There are 100 circular scale divisions. The…
In a screw gauge, $\displaystyle 5$ complete rotations of the screw cause it to move a linear distance of $\displaystyle 0.25$ cm . There are $\displaystyle 100$ circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of $\displaystyle 4$ main scale divisions and $\displaystyle 30$ circular scale divisions. Assuming negligible zero error, the thickness of the wire is :
Official answer
(2)
0.$\displaystyle 2150$ cm
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