Physics · 2018
JEE Main · 16 April 2018, Shift 1 · Q29
In a circuit for finding the resistance of a galvanometer by half deflection method, a 6 V battery and a high resistance of 11 k Ω are used. The…
In a circuit for finding the resistance of a galvanometer by half deflection method, a $\displaystyle 6$ V battery and a high resistance of $\displaystyle 11 \mathrm{k} \Omega$ are used. The figure of merit of the galvanometer is $\displaystyle 60 \mu \mathrm{~A} /$ division. In the absence of shunt resistance, the galvanometer produces a deflection of $\displaystyle \theta=9$ divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of $\displaystyle \theta / 2$, is closest to :
Official answer
(4)
$\displaystyle 110 \Omega$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.