If the time period t of the oscillation of a drop of liquid of density d, radius r, vibrating under surface tension s is given by the formula t=√(r^2…

If the time period $\displaystyle t$ of the oscillation of a drop of liquid of density $\displaystyle d$, radius $\displaystyle \boldsymbol{r}$, vibrating under surface tension $\displaystyle s$ is given by the formula $\displaystyle t=\sqrt{r^{2 b} s^c d^{a / 2}}$. It is observed that the time period is directly proportional to $\displaystyle \sqrt{\frac{d}{s}}$. The value of $\displaystyle b$ should therefore be :