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Physics · 2021

JEE Main · 26 August 2021, Shift 2 · Q25

If the maximum value of accelerating potential provided by a radio frequency oscillator is 12 kV. The number of revolution made by a proton in a…

If the maximum value of accelerating potential provided by a radio frequency oscillator is $\displaystyle 12$ kV . The number of revolution made by a proton in a cyclotron to achieve one sixth of the speed of light is \_\_\_\_. $\displaystyle \left[\mathrm{m}_{\mathrm{p}}=1.67 \times 10^{-27} \mathrm{~kg}, \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}\right.$, Speed of light $\displaystyle \left.=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right]$
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