Physics · 2019
JEE Main · 11 January 2019, Shift 2 · Q1
If speed (V), acceleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be:
If speed (V), acceleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be :
Official answer
(1)
$\displaystyle \mathrm{V}^{-4} \mathrm{~A}^2 \mathrm{~F}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.