If R is the radius of the earth and the acceleration due to gravity on the surface of earth is g =π^2 m / s^2, then the length of the second's…

If $\displaystyle R$ is the radius of the earth and the acceleration due to gravity on the surface of earth is $\displaystyle \mathrm{g}=\pi^2 \mathrm{~m} / \mathrm{s}^2$, then the length of the second's pendulum at a height $\displaystyle \mathrm{h}=2 \mathrm{R}$ from the surface of earth will be,: