Physics · 2024
JEE Main · 8 April 2024, Shift 2 · Q31
If ε_0 is the permittivity of free space and E is the electric field, then ε_0 E^2 has the dimensions:
If $\displaystyle \epsilon_0$ is the permittivity of free space and E is the electric field, then $\displaystyle \epsilon_0 \mathrm{E}^2$ has the dimensions :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \left[\mathrm{M} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right]$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.