Physics · 2022
JEE Main · 26 June 2022, Shift 1 · Q45
If Electric field intensity of a uniform plane electro magnetic wave is given as E =-301.6 sin ( k z-ω t ) a_x+452.4 sin ( k z-ω t ) a_y V/m. Then,…
If Electric field intensity of a uniform plane electro magnetic wave is given as
$$\mathrm{E}=-301.6 \sin (\mathrm{k} z-\omega \mathrm{t}) \hat{\mathrm{a}}_x+452.4 \sin (\mathrm{k} z-\omega \mathrm{t}) \hat{\mathrm{a}}_y \frac{\mathrm{~V}}{\mathrm{~m}} .
$$
Then, magnetic intensity ' H ' of this wave in $\displaystyle \mathrm{Am}^{-1}$ will be :
[Given : Speed of light in vacuum $\displaystyle \mathrm{c}=3 \times 10^8 \mathrm{~ms}^{-1}$, Permeability of vacuum
$$\left.\mu_0=4 \pi \times 10^{-7} \mathrm{NA}^{-2}\right]
$$
Official answer
(3)
$\displaystyle -0.8 \sin (\mathrm{k} z-\omega \mathrm{t}) \hat{\mathrm{a}}_y-1.2 \sin (\mathrm{k} z-\omega \mathrm{t}) \hat{\mathrm{a}}_x$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.