Physics · 2022
JEE Main · 27 July 2022, Shift 1 · Q37
If K_1 and K_2 are the thermal conductivities, L_1 and L_2 are the lengths and A_1 and A_2 are the cross sectional areas of steel and copper rods…
If $\displaystyle K_1$ and $\displaystyle K_2$ are the thermal conductivities, $\displaystyle L_1$ and $\displaystyle L_2$ are the lengths and $\displaystyle A_1$ and $\displaystyle A_2$ are the cross sectional areas of steel and copper rods respectively such that $\displaystyle \frac{K_2}{K_1}=9, \frac{A_1}{A_2}=2, \frac{L_1}{L_2}=2$. Then, for the arrangement as shown in the figure, the value of temperature T of the steel - copper junction in the steady state will be :

Official answer
(3)
$\displaystyle 45$°C
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.