Physics · 2023
JEE Main · 12 April 2023, Shift 1 · Q54
Glycerin of density 1.25 × 10^3 kg m^-3 is flowing through the conical section of pipe. The area of cross-section of the pipe at its ends are 10 cm^2…
Glycerin of density $\displaystyle 1.25 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ is flowing through the conical section of pipe. The area of cross-section of the pipe at its ends are $\displaystyle 10 \mathrm{~cm}^2$ and $\displaystyle 5 \mathrm{~cm}^2$ and pressure drop across its length is $\displaystyle 3 \mathrm{Nm}^{-2}$. The rate of flow of glycerin through the pipe is $\displaystyle x \times 10^{-5} \mathrm{~m}^3 \mathrm{~s}^{-1}$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.