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Physics · 2015
JEE Main 2015 · 2015-04-04 Offline · Q7
From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V =0…
From a solid sphere of mass M and radius R, a spherical portion of radius $\displaystyle \frac{R}{2}$ is removed, as shown in the figure. Taking gravitational potential $\displaystyle \mathrm{V}=0$ at $\displaystyle \mathrm{r}=\infty$, the potential at the centre of the cavity thus formed is :
$\displaystyle (G=$ gravitational constant $\displaystyle )$
Official answer
(2)
$\displaystyle \frac{- \text { GM }}{R}$
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.