Physics · 2021
JEE Main · 24 February 2021, Shift 1 · Q3
Four identical particles of equal masses 1 kg made to move along the circumference of a circle of radius 1 m under the action of their own mutual…
Four identical particles of equal masses $\displaystyle 1$ kg made to move along the circumference of a circle of radius $\displaystyle 1$ m under the action of their own mutual gravitational attraction. The speed of each particle will be :
Official answer
(1)
$\displaystyle \frac{\sqrt{(1+2 \sqrt{2}) \mathrm{G}}}{2}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.