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Physics · 2022

JEE Main · 25 June 2022, Shift 2 · Q51

For z=a^2 x^3 y^(1/2), where ' a ' is a constant. If percentage error in measurement of ' x ' and ' y ' are 4% and 12%, respectively, then the…

For $\displaystyle z=a^2 x^3 y^{\frac{1}{2}}$, where ' $\displaystyle a$ ' is a constant. If percentage error in measurement of ' $\displaystyle x$ ' and ' $\displaystyle y$ ' are $\displaystyle 4$% and $\displaystyle 12$%, respectively, then the percentage error for ' $\displaystyle z$ ' will be \_\_\_\_ %.
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.