Physics · 2024
JEE Main · 6 April 2024, Shift 1 · Q53
For three vectors A =(-x i -6 j -2 k ), B =(- i +4 j +3 k ) and C =(-8 i - j +3 k ), if A ·( B × C )=0, then value of x is ____.
For three vectors $\displaystyle \vec{A}=(-x \hat{i}-6 \hat{j}-2 \hat{k}), \vec{B}=(-\hat{i}+4 \hat{j}+3 \hat{k})$ and $\displaystyle \vec{C}=(-8 \hat{i}-\hat{j}+3 \hat{k})$, if $\displaystyle \vec{A} \cdot(\vec{B} \times \vec{C})=0$, then value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
4
More from Vectors
- A vector has magnitude same as that of A=3 i+4 j and is parallel to B=4 i+3 j. The x and y components of this vector in first quadrant are x and 3…2024
- When the position vector r=x i+y j+z k changes sign as - r, which one of the following vector will not flip under sign change?2026
- If two vectors A and B having equal magnitude R are inclined at an angle θ, then2024
- Two forces F̄_1 and F̄_2 are acting on a body. One force has magnitude thrice that of the other force and the resultant of the two forces is equal to…2024
- Two particles are located at equal distance from origin. The position vectors of those are represented by Ā=2 i+3 n j+2 k and B̄=2 i-2 j+4 p k,…2025
- The angle between vector Q and the resultant of (2 Q+2 P) and (2 Q-2 P) is:2024
JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.