Physics · 2019
JEE Main · 8 April 2019, Shift 1 · Q17
For the circuit shown, with R_1=1.0 Ω, R_2=2.0 Ω, E_1=2 V and E_2= E_3=4 V, the potential difference between the points 'a' and 'b' is approximately…
For the circuit shown, with $\displaystyle \mathrm{R}_1=1.0 \Omega$, $\displaystyle \mathrm{R}_2=2.0 \Omega, \mathrm{E}_1=2 \mathrm{~V}$ and $\displaystyle \mathrm{E}_2=\mathrm{E}_3=4 \mathrm{~V}$, the potential difference between the points 'a' and 'b' is approximately ( in V) :
Official answer
(2)
$\displaystyle 3.3$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.