Physics · 2021
JEE Main · 27 August 2021, Shift 2 · Q10
Figure shows a rod AB, which is bent in a 120° circular arc of radius R. A charge (-Q) is uniformly distributed over rod AB. What is the electric…
Figure shows a rod AB, which is bent in a $\displaystyle 120$° circular arc of radius R. A charge (-Q) is uniformly distributed over rod AB . What is the electric field $\displaystyle \overrightarrow{\mathrm{E}}$ at the centre of curvature O ?
Official answer
(1)
$\displaystyle \frac{3 \sqrt{3} Q}{8 \pi^2 \varepsilon_0 R^2}(\hat{i})$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.