Physics · 2023
JEE Main · 31 January 2023, Shift 1 · Q27
Expression for an electric field is given by E =4000 x^2 i V/m. The electric flux through the cube of side 20 cm when placed in electric field (as…
Expression for an electric field is given by $\displaystyle \overrightarrow{\mathrm{E}}=4000 x^2 \hat{i} \frac{\mathrm{~V}}{\mathrm{~m}}$. The electric flux through the cube of side $\displaystyle 20$ cm when placed in electric field (as shown in the figure) is $\displaystyle \_\_\_\_$ V cm.
Official answer
From NTA’s final answer key for this paper.
640
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.