Physics · 2025
JEE Main · 29 January 2025, Shift 1 · Q34
Consider I_1 and I_2 are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L_1= self inductance of coil 1, M_12= mutual…
Consider $\displaystyle \mathrm{I}_1$ and $\displaystyle \mathrm{I}_2$ are the currents flowing simultaneously in two nearby coils $\displaystyle 1$ & $\displaystyle 2$, respectively. If $\displaystyle \mathrm{L}_1=$ self inductance of coil $\displaystyle 1, \mathrm{M}_{12}=$ mutual inductance of coil $\displaystyle 1$ with respect to coil $\displaystyle 2$, then the value of induced emf in coil $\displaystyle 1$ will be
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \varepsilon_1=-\mathrm{L}_1 \frac{\mathrm{dI}_1}{\mathrm{dt}}-\mathrm{M}_{12} \frac{\mathrm{dI}_2}{\mathrm{dt}}$
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