Physics · 2020
JEE Main · 8 January 2020, Shift 1 · Q6
Consider a solid sphere of radius R and mass density ρ( r )=ρ_0(1-(r^2)/(R^2)), 0< r ≤ R. The minimum density of a liquid in which it will float is:
Consider a solid sphere of radius R and mass density $\displaystyle \rho(\mathrm{r})=\rho_0\left(1-\frac{\mathrm{r}^2}{\mathrm{R}^2}\right)$, $\displaystyle 0<\mathrm{r} \leq \mathrm{R}$. The minimum density of a liquid in which it will float is :
Official answer
(3)
$\displaystyle \frac{2 \rho_0}{5}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.