Physics · 2025
JEE Main · 28 January 2025, Shift 1 · Q35
Consider a long thin conducting wire carrying a uniform current I. A particle having mass " M " and charge " q " is released at a distance " a " from…
Consider a long thin conducting wire carrying a uniform current I . A particle having mass " M " and charge " q " is released at a distance " $\displaystyle a$ " from the wire with a speed $\displaystyle \mathrm{v}_{\mathrm{o}}$ along the direction of current in the wire. The particle gets attracted to the wire due to magnetic force. The particle turns round when it is at distance $\displaystyle x$ from the wire. The value of $\displaystyle x$ is
[ $\displaystyle \mu_0$ is vacuum permeability]
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle a e^{-\frac{4 \pi m v_{\mathrm{o}}}{q \mu_{\mathrm{o}} I}}$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.