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Physics · 2025

JEE Main · 4 April 2025, Shift 1 · Q50

Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of 1/(√ 2) Tesla, perpendicular to its plane. When conductor is pulled…

Conductor wire ABCDE with each arm $\displaystyle 10$ cm in length is placed in magnetic field of $\displaystyle \frac{1}{\sqrt{2}}$ Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of $\displaystyle 10 \mathrm{~cm} / \mathrm{s}$, induced emf between points A and E is $\displaystyle \_\_\_\_$ mV. Figure: JEE Main Physics 2025, Electromagnetic Induction
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.