Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q15
Charge is distributed within a sphere of radius R with a volume charge density ρ( r )=A/(r^2) e^-2 r / a, where A and a are constants. If Q is the…
Charge is distributed within a sphere of radius $\displaystyle R$ with a volume charge density $\displaystyle \rho(\mathrm{r})=\frac{\mathrm{A}}{\mathrm{r}^2} \mathrm{e}^{-2 \mathrm{r} / \mathrm{a}}$, where A and a are constants.
If Q is the total charge of this charge distribution, the radius R is :
Official answer
(2)
$\displaystyle \frac{\mathrm{a}}{2} \log \left(\frac{1}{1-\dfrac{\mathrm{Q}}{2 \pi \mathrm{aA}}}\right)$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.