SolveIt is under development
SolveItJEE Main
Physics · 2024

JEE Main · 9 April 2024, Shift 1 · Q55

At the centre of a half ring of radius R =10 cm and linear charge density 4 nC m^-1, the potential is x π V. The value of x is ____.

At the centre of a half ring of radius $\displaystyle \mathrm{R}=10 \mathrm{~cm}$ and linear charge density $\displaystyle 4 \mathrm{nC} \mathrm{m}^{-1}$, the potential is $\displaystyle x \pi V$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
ShareWhatsAppTelegram

More from Electrostatics

JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.