Physics · 2024
JEE Main · 9 April 2024, Shift 1 · Q55
At the centre of a half ring of radius R =10 cm and linear charge density 4 nC m^-1, the potential is x π V. The value of x is ____.
At the centre of a half ring of radius $\displaystyle \mathrm{R}=10 \mathrm{~cm}$ and linear charge density $\displaystyle 4 \mathrm{nC} \mathrm{m}^{-1}$, the potential is $\displaystyle x \pi V$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
36
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.