Physics · 2018
JEE Main · 15 April 2018, Shift 2 · Q8
As shown in the figure, forces of 10^5 N each are applied in opposite directions, on the upper and lower faces of a cube of side 10 cm, shifting the…
As shown in the figure, forces of $\displaystyle 10^5 \mathrm{~N}$ each are applied in opposite directions, on the upper and lower faces of a cube of side $\displaystyle 10$ cm, shifting the upper face parallel to itself by $\displaystyle 0.5$ cm. If the side of another cube of the same material is $\displaystyle 20$ cm, then under similar conditions as above, the displacement will be :
Official answer
(1)
0.$\displaystyle 25$ cm
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.