Physics · 2015
JEE Main · 10 April 2015, Shift 1 · Q1
x and y displacements of a particle are given as x( t )= a sin ω t and y( t )= a sin 2 ω t. Its trajectory will look like:
$\displaystyle x$ and $\displaystyle y$ displacements of a particle are given as $\displaystyle x(\mathrm{t})=\mathrm{a} \sin \omega \mathrm{t}$ and $\displaystyle y(\mathrm{t})=\mathrm{a} \sin 2 \omega \mathrm{t}$. Its trajectory will look like :
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(3)
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.