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JEE Main 2015 · 2015-04-04 Offline · Q22

An inductor ( L =0.03 H ) and a resistor ( R =0.15 k Ω) are connected in series to a battery of 15V EMF in a circuit shown below. The key K_1 has…

An inductor $\displaystyle (\mathrm{L}=0.03 \mathrm{H})$ and a resistor $\displaystyle (\mathrm{R}=0.15 \mathrm{k} \Omega)$ are connected in series to a battery of 15V EMF in a circuit shown below. The key $\displaystyle \mathrm{K}_1$ has been kept closed for a long time. Then at $\displaystyle \mathrm{t}=0, \mathrm{~K}_1$ is opened and key $\displaystyle \mathrm{K}_2$ is closed simultaneously. At $\displaystyle \mathrm{t}=1 \mathrm{~ms}$, the current in the circuit will be : $\displaystyle \left(e^5 \cong 150\right)$ Figure: JEE Main Physics 2015, Electromagnetic Induction
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.