Physics · 2018
JEE Main · 15 April 2018, Shift 1 · Q20
An ideal capacitor of capacitance 0.2 μ F is charged to a potential difference of 10 V. The charging battery is then disconnected. The capacitor is…
An ideal capacitor of capacitance $\displaystyle 0.2 \mu \mathrm{~F}$ is charged to a potential difference of $\displaystyle 10$ V. The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance $\displaystyle 0.5$ mH. The current at a time when the potential difference across the capacitor is $\displaystyle 5$ V, is :
Official answer
(3)
0.$\displaystyle 17$ A
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.