Physics · 2022
JEE Main · 28 June 2022, Shift 2 · Q45
An EM wave propagating in x -direction has a wavelength of 8 mm. The electric field vibrating y -direction has maximum magnitude of 60 Vm^-1. Choose…
An EM wave propagating in $\displaystyle x$-direction has a wavelength of $\displaystyle 8$ mm. The electric field vibrating $\displaystyle y$-direction has maximum magnitude of $\displaystyle 60 \mathrm{Vm}^{-1}$. Choose the correct equations for electric and magnetic fields if the EM wave is propagating in vacuum :
Official answer
(2)
$\displaystyle \begin{aligned}
& \mathrm{E}_y=60 \sin \left[\frac{\pi}{4} \times 10^3\left(x-3 \times 10^8 \mathrm{t}\right)\right] \hat{j} \mathrm{Vm}^{-1} \\
& \mathrm{~B}_z=2 \times 10^{-7} \sin \left[\frac{\pi}{4} \times 10^3\left(x-3 \times 10^8 \mathrm{t}\right)\right] \hat{k} \mathrm{~T}
\end{aligned}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.