Physics · 2024
JEE Main · 8 April 2024, Shift 1 · Q57
An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3 μ T perpendicular to its direction. An electric field E is…
An electron with kinetic energy $\displaystyle 5$ eV enters a region of uniform magnetic field of $\displaystyle 3$ $\displaystyle \mu \mathrm{T}$ perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E , so that electron moves along the same path, is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{NC}^{-1}$.
(Given, mass of electron $\displaystyle =9 \times 10^{-31} \mathrm{~kg}$, electric charge $\displaystyle =1.6 \times 10^{-19} \mathrm{C}$ )
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.