Physics · 2019
JEE Main · 11 January 2019, Shift 2 · Q15
An electric field of 1000 V / m is applied to an electric dipole at angle of 45^°. The value of electric dipole moment is 10^-29 C. m. What is the…
An electric field of $\displaystyle 1000 \mathrm{~V} / \mathrm{m}$ is applied to an electric dipole at angle of $\displaystyle 45^{\circ}$. The value of electric dipole moment is $\displaystyle 10^{-29} \mathrm{C} . \mathrm{m}$. What is the potential energy of the electric dipole?
Official answer
(1)
$\displaystyle -7 \times 10^{-27} \mathrm{~J}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.