Physics · 2024
JEE Main · 29 January 2024, Shift 2 · Q40
An electric field is given by (6 i +5 j +3 k ) N / C. The electric flux through a surface area 30 i m^2 lying in YZ -plane (in SI unit) is:
An electric field is given by $\displaystyle (6 \hat{i}+5 \hat{j}+3 \hat{k}) \mathrm{N} / \mathrm{C}$. The electric flux through a surface area $\displaystyle 30 \hat{i} \mathrm{~m}^2$ lying in YZ -plane (in SI unit) is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 180$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.