Physics · 2020
JEE Main · 9 January 2020, Shift 1 · Q11
An electric dipole of moment p =(- i -3 j +2 k ) × 10^-29 C.m is at the origin (0,0,0). The electric field due to this dipole at r =+ i +3 j +5 k…
An electric dipole of moment $\displaystyle \overrightarrow{\mathrm{p}}=(-\hat{i}-3 \hat{j}+2 \hat{k}) \times 10^{-29} \mathrm{C.m}$ is at the origin $\displaystyle (0,0,0)$. The electric field due to this dipole at $\displaystyle \overrightarrow{\mathbf{r}}=+\hat{i}+3 \hat{j}+5 \hat{k}$
(note that $\displaystyle \vec{r} \cdot \vec{p}=0$ ) is parallel to :
Official answer
(2)
$\displaystyle (+\hat{i}+3 \hat{j}-2 \hat{k})$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.