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Physics · 2019

JEE Main · 11 January 2019, Shift 1 · Q28

An amplitude modulated signal is given by V(t)=10[1+0.3 cos (2.2 × 10^4 t)] sin (5.5 × 10^5 t). Here t is in seconds. The sideband frequencies (in…

An amplitude modulated signal is given by $$V(t)=10\left[1+0.3 \cos \left(2.2 \times 10^4 t\right)\right] \sin \left(5.5 \times 10^5 t\right) . $$ Here t is in seconds. The sideband frequencies (in kHz ) are, [Given $\displaystyle \pi=22 / 7$ ]
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