Physics · 2025
JEE Main · 24 January 2025, Shift 1 · Q33
An air bubble of radius 0.1 cm lies at a depth of 20 cm below the free surface of a liquid of density 1000 kg / m^3. If the pressure inside the…
An air bubble of radius $\displaystyle 0.1$ cm lies at a depth of $\displaystyle 20$ cm below the free surface of a liquid of density $\displaystyle 1000 \mathrm{~kg} / \mathrm{m}^3$. If the pressure inside the bubble is $\displaystyle 2100 \mathrm{~N} / \mathrm{m}^2$ greater than the atmospheric pressure, then the surface tension of the liquid in SI unit is (use $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 0.05$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.