Physics · 2026
JEE Main · 5 April 2026, Shift 1 · Q44
An a.c. source of angular frequency ω is connected across a resistor R and a capacitor C in series. The current is observed as I. Now the frequency…
An a.c. source of angular frequency $\displaystyle \omega$ is connected across a resistor $\displaystyle R$ and a capacitor $\displaystyle C$ in series. The current is observed as $\displaystyle I$. Now the frequency of the source is changed to $\displaystyle \omega / 4$, (keeping the voltage unchanged) the current is found to be $\displaystyle I / 3$. The ratio of resistance to reactance at frequency $\displaystyle \omega$ is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \sqrt{\frac{7}{8}}$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.