Physics · 2024
JEE Main · 5 April 2024, Shift 2 · Q56
A wire of resistance 20 Ω is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now…
A wire of resistance $\displaystyle 20 \Omega$ is divided into $\displaystyle 10$ equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is $\displaystyle \_\_\_\_ \Omega$
Official answer
From NTA’s final answer key for this paper.
5
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.