Physics · 2015
JEE Main · 11 April 2015, Shift 1 · Q14
A wire, of length L (=20 cm ), is bent into a semi-circular arc. If the two equal halves, of the arc, were each to be uniformly charged with charges…
A wire, of length $\displaystyle \mathrm{L}(=20 \mathrm{~cm})$, is bent into a semi-circular arc. If the two equal halves, of the arc, were each to be uniformly charged with charges $\displaystyle \pm \mathrm{Q},\left[|\mathrm{Q}|=10^3 \varepsilon_0\right.$ Coulomb where $\displaystyle \varepsilon_0$ is the permittivity (in SI units) of free space] the net electric field at the centre O of the semi-circular arc would be :

Official answer
(2)
$\displaystyle \left(25 \times 10^3 \mathrm{~N} / \mathrm{C}\right) \hat{\mathrm{i}}$
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.