Physics · 2020
JEE Main · 9 January 2020, Shift 2 · Q11
A wire of length L and mass per unit length 6.0 × 10^-3 kgm^-1 is put under tension of 540 N. Two consecutive frequencies that it resonates at are:…
A wire of length $\displaystyle L$ and mass per unit length $\displaystyle 6.0 \times 10^{-3} \mathrm{kgm}^{-1}$ is put under tension of $\displaystyle 540$ N. Two consecutive frequencies that it resonates at are: $\displaystyle 420$ Hz and $\displaystyle 490$ Hz . Then L in meters is :
Official answer
(3)
2.$\displaystyle 1$ m
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.