Physics · 2020
JEE Main · 2 September 2020, Shift 2 · Q23
A wire of density 9 × 10^-3 kg cm^-3 is stretched between two clamps 1 m apart. The resulting strain in the wire is 4.9 × 10^-4. The lowest frequency…
A wire of density $\displaystyle 9 \times 10^{-3} \mathrm{~kg} \mathrm{~cm}^{-3}$ is stretched between two clamps $\displaystyle 1$ m apart. The resulting strain in the wire is $\displaystyle 4.9 \times 10^{-4}$. The lowest frequency of the transverse vibrations in the wire is (Young's modulus of wire $\displaystyle \mathrm{Y}=9 \times 10^{10}$ $\displaystyle \mathrm{Nm}^{-2}$ ), (to the nearest integer), \_\_\_\_.
Official answer
35
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.