A wire of density 8 × 10^3 kg / m^3 is stretched between two clamps 0.5 m apart. The extension developed in the wire is 3.2 × 10^-4 m. If Y =8 ×…

A wire of density $\displaystyle 8 \times 10^3 \mathrm{~kg} / \mathrm{m}^3$ is stretched between two clamps $\displaystyle 0.5$ m apart. The extension developed in the wire is $\displaystyle 3.2 \times 10^{-4} \mathrm{~m}$. If $\displaystyle \mathrm{Y}=8 \times 10^{10} \mathrm{~N} / \mathrm{m}^2$, the fundamental frequency of vibration in the wire will be $\displaystyle \_\_\_\_$ Hz